If you have three resistors in parallel and they each have 4 Ω of resistance, what is the total resistance in the circuit?

To find the total resistance of resistors connected in parallel, the formula used is:

[

\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

]

In this case, since each resistor has a resistance of 4 Ω, the equation becomes:

[

\frac{1}{R_{total}} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4}

]

This simplifies to:

[

\frac{1}{R_{total}} = \frac{3}{4}

]

To find ( R_{total} ), you take the reciprocal of ( \frac{3}{4} ):

[

R_{total} = \frac{4}{3} \approx 1.33 , \Omega

]

Thus, the correct answer is approximately 1.33 Ω, as it represents the total resistance in the circuit when multiple resistors of equal value are placed in parallel. This smaller total resistance compared to the individual resistor values highlights the principle that the total resistance in a parallel circuit decreases